Advance Surveying Sheet 17

1) Question.

The distance between the mirror control point and the principal point should be equal to
Answer.
- 1
  
  base line of the left photograph of streo pair
- 2
  
  base line of the right photograph of streo pair
- 3
  
  sum of the base lines of streo pair
- 4
  
  mean of the lines of the streo pair
Answer: 4

Explanation:
2) Question.

When a star is between the pole and the horizon,thje relationship between latitude ( $λ$ ),zenith distance (z) and declination $8$ ,is
Answer.
- 1
  
  $θ = z + 8$
- 2
  
  $θ = 8 - z$
- 3
  
  $θ = 180^{0} - (z + 8)$
- 4
  
  $θ = (z + 8) - 180^{0}$
Answer: 3

Explanation:
3) Question.

If $α$ ,H, and $8$ be the altitude hour angle azimuth and the declination of a circumpolar star at its elongation,in latitude $λ$ , the following relation holds good
Answer.
- 1
  
  cos H= $\frac{\tan λ}{\tan 8}$
- 2
  
  sin $α = \frac{\sin λ}{\sin 8}$
- 3
  
  sin A = $\frac{\cos 8}{\cos λ}$
- 4
  
  all the above
Answer: 4

Explanation:
4) Question.

The heavenly star in Q.No.5.81 is on the prime vertical,its Hour Angle (H) is given by the relation
Answer.
- 1
  
  cos H= $\frac{c o t 8}{\cos λ}$
- 2
  
  cos H= $\frac{\tan 8}{\tan λ}$
- 3
  
  tan H= $\frac{\sin 8}{\sin λ}$
- 4
  
  tan H= $\frac{\cos 8}{\cos λ}$
Answer: 2

Explanation:
5) Question.

If $8$ is the declination of the polaris and $λ$ is the latitude of the place, the azimuth of the polaris ,is
Answer.
- 1
  
  $\frac{\cos 8}{\cos λ}$
- 2
  
  $\frac{\cos (90^{0} - 8)}{\cos (90^{0} - λ)}$
- 3
  
  $\frac{\sin (90^{0} - 8)}{\sin (90^{0} - λ)}$
- 4
  
  $\frac{\tan (90^{0} + 8)}{\tan (90^{0} + λ)}$
Answer: 1

Explanation:
6) Question.

If $θ$ and $8$ be the latitude of an observer and declination of a heavenly body respectively,the upper culmination of the body will be south of zenith distance,is
Answer.
- 1
  
  $8 - θ$
- 2
  
  $θ - 8$
- 3
  
  $θ + 8$
- 4
  
  $\frac{1}{2} (θ - 8)$
Answer: 2

Explanation:
7) Question.

If $θ$ and $8$ be the latitude of a place and declination of a star respectively,the upper culmination of the star will be north of zenith if its zenith distance,is
Answer.
- 1
  
  $8 - θ$
- 2
  
  $θ - 8$
- 3
  
  $θ + 8$
- 4
  
  $\frac{θ + 8}{2}$
Answer: 1

Explanation:
8) Question.

Pick up the incorrect statement from the following: $\cdot$
Answer.
- 1
  
  In truly vertical photographs without relief angles are true at the plumb point
- 2
  
  In tilted photographs without relief,angles are true at the iso-centre
- 3
  
  In tilled photographs with relief,angles are true at the principal point.
- 4
  
  none of these
Answer: 3

Explanation:
9) Question.

ina truly vertical photograph,
Answer.
- 1
  
  iso-centre coincides the plumb point
- 2
  
  plumb point coincides the principal point
- 3
  
  principal point,iso-centre and plumb point coincide
- 4
  
  all the above
Answer: 4

Explanation:
10) Question.

If the general ground level of any area is 10% of the flying height,the principal points may be used as the centres of radial directions for small scale mapping even in tilted photograph up to
Answer.
- 1
  
  $1^{0}$
- 2
  
  $2^{0}$
- 3
  
  $3^{0}$
- 4
  
  $4^{0}$
Answer: 3

Explanation:

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