The heavenly star in Q.No.5.81 is on the prime vertical,its Hour Angle (H) is given by the relation

- 1
  
  cos H= $\frac{c o t 8}{\cos λ}$
- 2
  
  cos H= $\frac{\tan 8}{\tan λ}$
- 3
  
  tan H= $\frac{\sin 8}{\sin λ}$
- 4
  
  tan H= $\frac{\cos 8}{\cos λ}$

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