If $8$ is the declination of the polaris and $λ$ is the latitude of the place, the azimuth of the polaris ,is

- 1
  
  $\frac{\cos 8}{\cos λ}$
- 2
  
  $\frac{\cos (90^{0} - 8)}{\cos (90^{0} - λ)}$
- 3
  
  $\frac{\sin (90^{0} - 8)}{\sin (90^{0} - λ)}$
- 4
  
  $\frac{\tan (90^{0} + 8)}{\tan (90^{0} + λ)}$

Display Comments

Leave a comment

Login at first then you can submit comment. Click here to login.