If $θ$ and $8$ be the latitude of an observer and declination of a heavenly body respectively,the upper culmination of the body will be south of zenith distance,is

- 1
  
  $8 - θ$
- 2
  
  $θ - 8$
- 3
  
  $θ + 8$
- 4
  
  $\frac{1}{2} (θ - 8)$

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