Soil Mechanics and Foundation Sheet 27

1) Question.

The passive earth pressure is proportional to
Answer.
- 1
  
  $\tan^{2} (45^{0} + \frac{ϕ}{2})$
- 2
  
  $\tan^{2} (45^{0} - \frac{ϕ}{2})$
- 3
  
  $c o t^{2} (45^{0} + \frac{ϕ}{2})$
- 4
  
  $c o t^{2} (45^{0} - \frac{ϕ}{2})$
Answer: 1

Explanation:
2) Question.

The active earth pressure is proportional to

[ $ϕ$ = Angle of internal friction of soil]
Answer.
- 1
  
  $\tan^{2} (45^{0} + \frac{ϕ}{2})$
- 2
  
  $\tan^{2} (45^{0} - \frac{ϕ}{2})$
- 3
  
  $c o t^{2} (45^{0} + \frac{ϕ}{2})$
- 4
  
  $c o t^{2} (45^{0} - \frac{ϕ}{2})$
Answer: 3

Explanation:
3) Question.

The coefficient of active earth pressure for a looose sand having an angle of internal friction of $30^{0}$ , is
Answer.
- 1
  
  1/2
- 2
  
  1/3
- 3
  
  1
- 4
  
  3
Answer: 2

Explanation:
4) Question.

The net ultimate bearing capacity of a square footing in sand is given by
Answer.
- 1
  
  $0.3 γ B N_{γ} + γ D_{f} (N_{q} - 1)$
- 2
  
  $0.3 γ B N_{γ} + γ D_{f} (N_{q} + 1)$ $0.3 γ B N_{γ} + γ D_{f} (N_{q} + 1)$
- 3
  
  $0.4 γ B N_{γ} + γ D_{f} (N_{q} - 1)$
- 4
  
  $0.4 γ B N_{γ} + γ D_{f} (N_{q} + 1)$
Answer: 3

Explanation:

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