A simply supported beam .6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is $1400 k g / m^{2}$ , the area of steel required, is

- 1
  
  $14 c m^{2}$
- 2
  
  $15 c m^{2}$
- 3
  
  $16 c m^{2}$
- 4
  
  $17 c m^{2}$

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