A pile weighing $W_{1}$ kg penetrates S metres with its last blow. If $W_{2}$ is the weight of the hammer having a drop of H metres, the pile can carry a maximum external load

- 1
  
  $\frac{W_{1}^{2}}{W_{1} + W_{2}} . \frac{H}{S} + W_{1} k g$
- 2
  
  $\frac{W_{2}^{2}}{W_{1} + W_{2}} . \frac{H}{S} + W_{2} k g$
- 3
  
  $\frac{W_{1}^{2}}{W_{1} - W_{2}} . \frac{H}{S} + W_{1} k g$
- 4
  
  $\frac{W_{2}^{2}}{W_{1} + W_{2}} . \frac{H}{S} + W_{2} k g$

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