If the length of a combined footing for two columns l metres is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is

where $\bar{x}$ is the distance of centre of gravity of column loads.

- 1
  
  $y = L - (l - \bar{x})$
- 2
  
  $y = \frac{L}{2} + (l - \bar{x})$
- 3
  
  $y = \frac{L}{2} - (l + \bar{x})$
- 4
  
  $y = \frac{L}{2} - (l - \bar{x})$

Display Comments

Leave a comment

Login at first then you can submit comment. Click here to login.