If the bearing capacity of soil is $10 t o n n e s / c m^{2}$ and the projection of plain concrete footing from walls, is a cm, the depth D of footing is

- 1
  
  D=0.0775 a
- 2
  
  D=0.775 a
- 3
  
  $D = 0.775 \sqrt{a}$
- 4
  
  $D = 0.775 a^{2}$

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