If permissible compressive stress in concrete is $50 k g / c m^{2}$ , tensile stress in steel is $1400 k g / c m^{2}$ and modular ratio is 18, the depth d of the beam, is

- 1
  
  $d = \sqrt{\frac{0.11765 x B . M .}{b r e a d t h}}$
- 2
  
  $d = \sqrt{\frac{0.22765 x B . M .}{b r e a d t h}}$
- 3
  
  $d = \sqrt{\frac{0.33765 x B . M .}{b r e a d t h}}$
- 4
  
  $d = \sqrt{\frac{0.44765 x B . M .}{b r e a d t h}}$

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