If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by

- 1
  
  $\frac{5}{6} \frac{r}{1 + r^{2}} M$
- 2
  
  $\frac{5}{6} \frac{r^{2}}{1 + r^{2}} M$
- 3
  
  $\frac{5}{6} \frac{r^{2}}{1 + r^{3}} M$
- 4
  
  $\frac{5}{6} \frac{r^{2}}{1 + r^{4}} M$

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