When the radius of gyration of a tension member is r, the maximum allowable bending stress in tension is $σ_{^{b}}$ , the distance to the extreme fibre from the neutral axis is y and the bending moment is M when the member is subjected to pure bending, then the cross-sectional area (A) is given by

- 1
  
  $A = \frac{M y}{σ_{b} . r^{2}}$
- 2
  
  $A = \frac{M r^{2}}{σ_{b} . y}$
- 3
  
  $A = \frac{σ_{b} . r^{2}}{M y}$
- 4
  
  $A = \frac{σ_{b} . y}{M r^{2}}$

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