when a pair of angles back to back in tension are connected by one leg of each angle, the net effective area of the section $(A_{N})$ is taken as

- 1
  
  $A_{N} = a + \frac{b}{1 - 0.2 b / a}$
- 2
  
  $A_{N} = a + \frac{b}{1 + 0.2 b / a}$
- 3
  
  $A_{N} = a + \frac{b}{1 - 0.33 b / a}$
- 4
  
  $A_{N} = a + \frac{b}{1 + 0.33 b / a}$

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