If a sample of dry sand tested in direct shear test gives failure shear stress $t_{f} a s 1 k g / c m^{2}$ at a normal stress $σ_{f} a s 2 k g / c m^{2}$ , then the angle of internal friction of soil is given by

- 1
  
  $\tan^{- 1} (2)$
- 2
  
  $\tan^{- 1} (1)$
- 3
  
  $\tan^{- 1} (1 / 2)$
- 4
  
  $\tan^{- 1} (1 / 4)$

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