A cast-in-situ bored pile 0.50 m diameter and 10 m deep is placed in a purely cohesive soil. If the cohesion of the soil is $4 t / m^{2}$ and adhesion between the pile and the soil is half the value of cohesion, then the ultimate bearing capacity of the pile is given by

- 1
  
  $\frac{19 π}{4} t o n n e s$
- 2
  
  $\frac{29 π}{4} t o n n e s$
- 3
  
  $\frac{39 π}{4} t o n n e s$
- 4
  
  $\frac{49 π}{4} t o n n e s$

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