For a sandy soil, the angle of internal friction is $30^{0}$ . If the major principal stress is $50 k N / m^{2}$ at failure, the corresponding minor principal stress will be

- 1
  
  $12.2 k N / m^{2}$
- 2
  
  $16.66 k N / m^{2}$
- 3
  
  $20.8 k N / m^{2}$
- 4
  
  $27.2 k N / m^{2}$

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