For a trapezoidal channel section to be most economical, its hydraulic radius must be equal to

[y= the depth of flow]

- 1
  
  $\frac{y}{4}$
- 2
  
  $\frac{y}{2}$
- 3
  
  $\frac{y}{2 \sqrt{2}}$
- 4
  
  $\frac{y}{3 \sqrt{2}}$

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