The specific energy 'E' in a critical flow at depth $y_{c}$ occuring in a triangular channel is given by

- 1
  
  $E = 1.25 y_{c}$
- 2
  
  $E = 1.5 y_{c}$
- 3
  
  $E = 1.75 y_{c}$
- 4
  
  $E = 2 y_{c}$

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