The beam $A B C$ shown in Fig. 10.52 is horizontal

The distance to the point of contraflexure from the fixed end $' A'$ is

- 1
  
  $0.333 m$
- 2
  
  $0.666 m$
- 3
  
  $0.25 m$
- 4
  
  $0.75 m$

Display Comments

Leave a comment

Login at first then you can submit comment. Click here to login.