Two circular bars $A$ and $B$ of same material and same length are of diameters $D_{A}$ and $D_{B}$ respectively. The bars are

subjected to the same torque T. The ratio of strain energies stored in the bars $A$ and $B$ is proportional to

- 1
  
  $\frac{D_{A}}{D_{B}}$
- 2
  
  $\frac{D_{B}}{D_{A}}$
- 3
  
  ${(\frac{D_{A}}{D_{B}})}^{2}$
- 4
  
  ${(\frac{D_{B}}{D_{A}})}^{4}$

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