A simply supported beam ABC of length 1 carries a concentrated load P at an intermediate point B. If the slope at A is 0.75 times the slope at C, then the length of portion AB is equal to

- 1
  
  $\frac{3}{4} 1$
- 2
  
  $\frac{4}{7} 1$
- 3
  
  $\frac{5}{7} 1$
- 4
  
  $\frac{2}{7} 1$

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