A point in a strained body is subjected to a tensile stress of 100 MPa on one plane and a tensile stress of 50 MPa on a plane at right angle to it. If these planes are carrying shear stresses of 50 MPa, then the principal stresses are inclined to the larger normal stress at an angle

- 1
  
  $\tan^{- 1}$ $(2)$
- 2
  
  $\frac{1}{2} \tan^{- 1} (2)$
- 3
  
  $\frac{1}{2} \tan^{- 1} (\frac{2}{3})$
- 4
  
  $\frac{1}{2} \tan^{- 1} (\frac{1}{3})$

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