A rectangular timber beam is cut out of a cylindrical log of diameter $' D' .$ The depth of the strongest timber beam will be

- 1
  
  $D \sqrt{\frac{1}{2}}$
- 2
  
  $D \sqrt{\frac{2}{3}}$
- 3
  
  $D \sqrt{\frac{5}{8}}$
- 4
  
  $D \sqrt{\frac{3}{4}}$

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