A simply supported beam ABC of length l carries a concentrated load P at an intermediate point B. If the slope at A is 0.75 times the slope at C, then the length of portion AB is equal to

- 1
  
  $\frac{3}{4} l$
- 2
  
  $\frac{4}{7} l$
- 3
  
  $\frac{5}{7} l$
- 4
  
  $\frac{2}{7} l$

Display Comments

Leave a comment

Login at first then you can submit comment. Click here to login.